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| ES4408FD资料 | |
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ES4408FD PDF Download |
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File Size : 116 KB
Manufacturer:ESS Description:The IRU1050 keeps a constant 1.25V between the out- put pin and the adjust pin. By placing a resistor R1 across these two pins a constant current flows through R1, add- ing to the IADJ current and into the R2 resistor producing a voltage equal to the (1.25/R1)3R2 + IADJ3R2 which will be added to the 1.25V to set the output voltage. This is summarized in the above equation. Since the minimum load current requirement of the IRU1050 is 10mA, R1 is typically selected to be 121V resistor so that it automatically satisfies the minimum current re- quirement. Notice that since IADJ is typically in the range of 50mA it only adds a small error to the output voltage and should only be considered when a very precise out- put voltage setting is required. For example, in a typical 3.3V application where R1=121V and R2=200V the er- ror due to IADJ is only 0.3% of the nominal set point. |
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| 1PCS | 100PCS | 1K | 10K | ||
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型 号：ES4408FD 厂 家：ESS 封 装：QFP 批 号：02+ 数 量：480 说 明：绝对原装正品底价 |
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运 费： 所在地： 新旧程度： |
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| 联系人：龙先生,胡小姐 |
| 电 话：0755-83226907,83229025,83226903 |
| 手 机：13927436669 |
| QQ：1109170345,514620629 |
| MSN：hlh1999@msn.com |
| 传 真：0755-83226930 |
| EMail：sale@cdf-ic.com |
| 公司地址： 深圳市福田区中航路新亚洲电子商城国利大厦710室. |
